为什么a/sina等于b+c/sinb+sinc
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解决时间 2021-02-09 08:57
- 提问者网友:無理詩人
- 2021-02-08 15:51
为什么a/sina等于b+c/sinb+sinc
最佳答案
- 五星知识达人网友:洒脱疯子
- 2021-02-08 16:38
a/sinA =b/sinB=c/sinC =k
a= ksinA ,b= ksinB, c=k/sinC
a/sinA = k
(b+c)/(sinB+sinC)
=k(sinB+sinC)/(sinB+sinC)
=k
=a/sinA
a= ksinA ,b= ksinB, c=k/sinC
a/sinA = k
(b+c)/(sinB+sinC)
=k(sinB+sinC)/(sinB+sinC)
=k
=a/sinA
全部回答
- 1楼网友:执傲
- 2021-02-08 18:50
∵ 根据正弦定理:a/sinA=b/sinB=c/sinC=2R
∴b=2RsinB,c=2RsinC
∴ (b+c)/(sinB+sinC)=(2RsinB+2RsinC)/(sinB+sinC)
= 2R(sinB+sinC) /(sinB+sinC)
= 2R = a/sinA
∴b=2RsinB,c=2RsinC
∴ (b+c)/(sinB+sinC)=(2RsinB+2RsinC)/(sinB+sinC)
= 2R(sinB+sinC) /(sinB+sinC)
= 2R = a/sinA
- 2楼网友:我住北渡口
- 2021-02-08 18:44
由b/sinB=c/sinC 得 sinC/sinB=c/b 两边加1得 sinC/sinB+1=c/b +1 通分得
(sinC+sinB)/sinB=(b+c)/b 变形得(b+c)/(sinB+sinC) =b/sinB
既b/sinB=c/sinC=(b+c)/(sinB+sinC)
(sinC+sinB)/sinB=(b+c)/b 变形得(b+c)/(sinB+sinC) =b/sinB
既b/sinB=c/sinC=(b+c)/(sinB+sinC)
- 3楼网友:上分大魔王
- 2021-02-08 18:04
a/sinA=2R,b+c/sinB+sinC=2R(SinB+SinC)/sinB+sinC=2R,所以两式相等
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